Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they three years ago?

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Solution

Let seema's age be 'x' years
and sudesh's age be 'y' years
$\Rightarrow y = 2 x$
$\Rightarrow 4 (x - 6) = (y + 4)$
$\Rightarrow 4 (x - 6) = 2 (2 x + 4)$
$\Rightarrow 4 x - 2 x = 2 x + 4$
$\Rightarrow 2 x = 28$
$R i g h t a r r o w x = 14 y e a r s$
$y = 2 x = 28 y e a r s$
3 years ago seema was 11 years & sudesh was 25 years.

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Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and four years are added to Sudesh's age, Sudesh will be four times Seema's age. How old were they three years ago?

Let seema's age be 'x' yearsand sudesh's age be 'y' years⇒y=2x⇒4(x−6)=(y+4)⇒4(x−6)=2(2x+4)⇒4x−2x=2x+4⇒2x=28Rightarrowx=14yearsy=2x=28years3 years ago seema was 11 years & sudesh was 25 years.