Suggest the reagents for the following conversion.

Hg(OAc)₂, H₂O,NaBH₄

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B₂H₆/ether,H₂O,H₂O₂/OH^-

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H₂O/ $H^{+}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Grignard reagent

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
B₂H₆/ether,H₂O,H₂O₂/OH^-

Hydroboration-oxidation gives the less substituted alcohol as the major product, which is in accordance with the anti-Markovnikov's rule. Thus, a terminal alcohol will be obtained when boranes in ether or THF (tetrahydrofuran) along with alkaline hydrogen peroxide, is added to the given alkene.
A secondary alcohol will be formed on treatment with reagent (a) while reagent (c) will give a mixture of secondary and primary (minor product) alcohols.

Suggest Corrections

Similar questions

F e (C N)_{6}^{x -} + H_{2} O_{2} + H^{+} \to F e (C N)_{6}^{y -} + H_{2} O

[F e (C N_{6})]^{p -} + H_{2} O_{2} + O H^{-} \to [F e (C N_{6})]^{q -} + O_{2} + H_{2} O

C H_{3} C O O H + O H^{-} - ---- - \to C H_{3} C O O^{-} + H_{2} O

A H_{2} O - --- \to H_{2} S O_{4} B

A 1. H g (O A c)_{2}, H_{2} O - ---------- \to 2. N a B H_{4} B

A 1. B H_{3}, T H F - -------- \to 2. H_{2} O_{2}, O H^{-} B

C_{6} H_{6} + r e a g e n t \to C_{6} H_{5} N O_{2} + H_{2} O

Join BYJU'S Learning Program