Sujata scored 2240 marks in an examination that is 128 marks more than the minimum passing percentage of 64%. What is the percentage of marks obtained by Meena if she scores 907 marks less than Sujata?

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Solution

The correct option is B 40
If total maximum marks be x, then
$\frac{x \times 64}{100} = 2240 - 128 = 2112 \Rightarrow ? = \frac{2112 \times 100}{64} = 3300$
Marks obtained by Meena =2240-907=1333
Required percenage $= \frac{1333}{3300} \times 100 \approx 40$

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Sujata scored 2240 marks in an examination that is 128 marks more than the minimum passing percentage of 64%. What is the percentage of marks obtained by Meena if she scores 907 marks less than Sujata?

The correct option is B 40If total maximum marks be x, then x×64100=2240−128=2112⇒?=2112×10064=3300 Marks obtained by Meena =2240-907=1333 Required percenage =13333300×100≈40

The correct option is B 40
If total maximum marks be x, then
$\frac{x \times 64}{100} = 2240 - 128 = 2112 \Rightarrow ? = \frac{2112 \times 100}{64} = 3300$
Marks obtained by Meena =2240-907=1333
Required percenage $= \frac{1333}{3300} \times 100 \approx 40$