Sulphate of a metal ‘M’ (having amphoteric oxide) reacts with sodium hydroxide to form a white gelatinous precipitate. The chemical formula of the precipitate and metal ‘M’ respectively are

C u (O H)_{2} a n d C u

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N a_{2} Z n O_{2} a n d Z n

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CuO and Cu

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Z n (O H)_{2} a n d Z n

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Solution

The correct option is D $Z n (O H)_{2} a n d Z n$
The metal ‘M’ is zinc (Zn) as it has an amphoteric oxide, ZnO.

Zinc sulphate $(Z n S O_{4})$ reacts with sodium hydroxide (NaOH) to form a white gelatinous precipitate of zinc hydroxide $(Z n (O H)_{2})$ along with sodium sulphate $(N a_{2} S O_{4})$ . The chemical reaction between $Z n S O_{4}$ and NaOH is as given below:

$Z n S O_{4} + 2 N a O H \to Z n (O H)_{2} ↓ + N a_{2} S O_{4}$

Hence, the correct answer is option (d).

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