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Sulphuric Acid

Sulphur on re...

Question

Sulphur on reaction with $H_{2} S O_{4}$ gives __________ .

A

S O_{2}

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B

H_{2}

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C

S O_{3}

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D

H_{2} S

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Solution

The correct option is A $S O_{2}$
${2 H}_{2} {S O}_{4} + S \to {3 S O}_{2} + H_{2} O$

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Similar questions

S + O_{2} ⟶ S O_{2}

Δ H = - 398.2 k J

S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3}

Δ H = - 98.7 k J

S O_{3} + H_{2} O ⟶ H_{2} S O_{4}

Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O

Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298 K

Q. In the reaction,

2 H_{2} S + S O_{2} \to 2 H_{2} O + 3 S

S O_{2}

H_{2} S

will give how much sulphur?

Q. In the following reaction:

2 H_{2} S + S O_{2} ⟶ 2 H_{2} O + 3 S

1

S O_{2}

H_{2} S

will give sulphur equal to :

S + O_{2} \to S O_{2}; Δ H = - 398.2 k J; S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{2} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J; H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298

S + O_{2} \to S O_{2}; Δ H = - 298.2 k J

S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{3} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

the enthalpy of formation of

H_{2} S O_{4}

298

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