Sulphur reacts with chlorine in $1 : 2$ ratio and forms X. Hydrolysis of X gives a sulphur compound Y. what is the hybridization state of central atom in the compound Y?

s p^{3}

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s p^{2}

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s p

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d s p^{2}

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Solution

The correct option is A $s p^{3}$

Hybridisation of S in $H_{2} S O_{3} = \frac{1}{2} (6 + 2 + 0) = 4, s p^{3} (3 b o n d p a i r s + o n e l o n e p a i r)$

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Sulphur reacts with chlorine in 1:2 ratio and forms(X), X on hydrolysis gives a sulphur compound y.
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Sulphur reacts with chlorine in 1:2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. what is the hybridization state of central atom in the compound Y?

The correct option is A sp3 Hybridisation of S in H2SO3=12(6+2+0)=4,sp3 (3bond pairs + one lone pair)

Sulphur reacts with chlorine in $1 : 2$ ratio and forms X. Hydrolysis of X gives a sulphur compound Y. what is the hybridization state of central atom in the compound Y?

The correct option is A $s p^{3}$

Hybridisation of S in $H_{2} S O_{3} = \frac{1}{2} (6 + 2 + 0) = 4, s p^{3} (3 b o n d p a i r s + o n e l o n e p a i r)$