Sulphur reacts with chlorine in 1 : 2 ratio & forms ‘X’. Hydrolysis of ‘X’ gives a sulphur compound Y. What is the structure & Hybridization of anion of Y?

Tetrahedral,

s p^{3}

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Linear, sp

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Pyramidal,

s p^{3}

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Trigonal planar,

s p^{2}

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Solution

The correct option is C Pyramidal, $s p^{3}$
$S + 2 C l_{2} \to S C l_{4} (X)$

$S C l_{4} + 4 H_{2} O \to S (y) (O H)_{4} + 4 H C l$

$S (O H)_{4} \to S O_{3}^{- 2} + 2 H^{+} + H_{2} O \to H_{2} S O_{3} + H_{2} O$

Y is unstable & Anion of y is $S O_{3}^{- 2}$

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1 : 2

ratio and forms

X

. hydrolysis of

X

gives a sulphur compound

Y

. What is the hybridization state of central atom in the compound?

Q. Sulphur reacts with chlorine in

1 : 2

ratio and forms X. Hydrolysis of X gives a sulphur compound Y. what is the hybridization state of central atom in the compound Y?

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Sulphur reacts with chlorine in 1 : 2 ratio & forms ‘X’. Hydrolysis of ‘X’ gives a sulphur compound Y. What is the structure & Hybridization of anion of Y?

The correct option is C Pyramidal, sp3S+2Cl2→SCl4(X) SCl4+4H2O→S(y)(OH)4+4 HCl S(OH)4→SO−23+2H+ +H2O→H2SO3+H2O Y is unstable & Anion of y is SO−23

The correct option is C Pyramidal, $s p^{3}$
$S + 2 C l_{2} \to S C l_{4} (X)$

$S C l_{4} + 4 H_{2} O \to S (y) (O H)_{4} + 4 H C l$

$S (O H)_{4} \to S O_{3}^{- 2} + 2 H^{+} + H_{2} O \to H_{2} S O_{3} + H_{2} O$

Y is unstable & Anion of y is $S O_{3}^{- 2}$