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Question

Sulphur trioxide is prepared by the following two reactions:
S8(s)+8O2(g)8SO2(g)
2SO2(g)+O2(g)2SO3(g)
How many grams of SO3 are produced from 1 mole of S8?

A
1280.0
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B
640.0
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C
960.0
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D
320.0
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Solution

The correct option is A 640.0
S8(s)+8O2(g)8SO2(g)
2SO2(g)+O2(g)2SO3(g)
By stoichiometry, 1 mole of S8(s) produces 8 mole SO2(g)
Also, 2 mole of SO2(g) produces 2 mole SO3(g)
Therefore, 8 mole SO2(g) produces 8 moles SO3(g)
i.e. 1 mole S8(s) produces 8 moles SO3(g)
i.e. 8×80g of SO3
i.e 640g of SO3

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