Sulphuric acid and sodium hydroxide reacts to form sodium sulphate and water.

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Solution

$\underset{Sodium Hydroxide}{2 NaOH} + \underset{S u l p h u r i c A c i d}{H_{2} S O_{4}} \overset{}{\to} \underset{S o d i u m S u l p h a t e}{N a_{2} S O_{4}} + \underset{W a t e r}{2 H_{2} O}$

When sodium hydroxide reacts with sulphuric acid they form Sodium sulphate and water.
The reactants involved in the process are sodium hydroxide and sulfuric acid.
The reactants are base and an acid, which leads to a neutralization process and yields a salt

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Similar questions

Sulphuric acid reacts with sodium hydroxide as follows

$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$

When 1L of 0.1M sulphuric acid solutoin is allowed to react with 1L of 0.1M sodium hydroxide solutoin, the amount of sodium sulphate formed and its molarity in the solution obtained is ?

(a) $0.1 m o l L^{- 1}$ (b) $7.10 g$

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(g) Ammonia + oxygen $\to$ nitric oxide + water

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(q) Sodium chloride + manganese dioxide + sulphuric acid $\to$ sodium hydrogen sulphate + manganese sulphate + water + chlorine.

Copper sulphate reacts with sodium hydroxide to form a blue precipitate of copper hydroxide and sodium sulphate. In an experiment, 15.95 g of copper sulphate reacted with 8.0 g of sodium hydroxide to form 9.75 g of copper hydroxide and 14.2 g of sodium sulphate. Which law of chemical combination is illustrated by this data?

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