Question

Sum of 3 consecutive multiples of 5 is 345. Find the ratio of the highest multiple and the lowest multiple.

• A. $12:11$
• B. $13:12$
• C. $11:10$
• D. $14:13$

Answer 1

The correct option is A $12:11$

Let the multiples be $5(x-1),5x,5(x+1)$.
Given: Sum $=345$
$\therefore 5x-5+5x+5x+5=345\Rightarrow 15x=345\to x=23$
Thus, the multiples of 5 are $110,115,120$.
Ratio of the highest multiple and lowest mulitple $=120:110=12:11$