Sum of the digit of $2 -$ digit no. is $12$ . If the digits are reversed the new no. so formed increased by $36$ . Find the no.

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Solution

Let ab $2$ digit number
$a + b = 12$ ………. $(1)$
Given $(10 b + a) - (10 a + b) = 36$
$9 (b - a) = 36, b - a = 4$ ……… $(2)$
$a + b = 12$
$+ b - a = 4$
_____________
$2 b = 16$ , $b = 8$ , $a = 4$
$∴$ Number is $48$ .

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Sum of the digit of 2−digit no. is 12. If the digits are reversed the new no. so formed increased by 36. Find the no.

Let ab 2 digit numbera+b=12 ……….(1)Given (10b+a)−(10a+b)=369(b−a)=36,b−a=4 ………(2)a+b=12+b−a=4_____________2b=16, b=8, a=4∴ Number is 48.

Sum of the digit of $2 -$ digit no. is $12$ . If the digits are reversed the new no. so formed increased by $36$ . Find the no.

Let ab $2$ digit number
$a + b = 12$ ………. $(1)$
Given $(10 b + a) - (10 a + b) = 36$
$9 (b - a) = 36, b - a = 4$ ……… $(2)$
$a + b = 12$
$+ b - a = 4$
_____________
$2 b = 16$ , $b = 8$ , $a = 4$
$∴$ Number is $48$ .