The ten's digit of a two digit no. exceeds the units digit by 5. If the digits are reversed, the new number is less by 45. If the sum of their digits is 9, find the nos.

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Solution

Let the units digit be y,
and the tens digit be x.
Thus the number is 10x+y
according to the condition,
(10x+y)-(10y+x) =45
9(x - y)=45
x-y=5.......(1)
also x+y=9...(given)
Adding(1) and (2)

2x=14
x=7
Putting in (1)
y=7-5
y=2

Thus the number is 72.

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The ten's digit of a two digit no. exceeds the units digit by 5. If the digits are reversed, the new number is less by 45. If the sum of their digits is 9, find the nos.

Let the units digit be y, and the tens digit be x. Thus the number is 10x+y according to the condition, (10x+y)-(10y+x) =45 9(x - y)=45 x-y=5.......(1) also x+y=9...(given) Adding(1) and (2) 2x=14 x=7 Putting in (1) y=7-5 y=2 Thus the number is 72.

Let the units digit be y,
and the tens digit be x.
Thus the number is 10x+y
according to the condition,
(10x+y)-(10y+x) =45
9(x - y)=45
x-y=5.......(1)
also x+y=9...(given)
Adding(1) and (2)

2x=14
x=7
Putting in (1)
y=7-5
y=2

Thus the number is 72.