The ten's digit of a two digit number exceeds its unit's digit by $4$ . If the ten's digit and the unit's digit are in the ratio $3 : 1$ , find the number.

62

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51

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65

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85

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Solution

The correct option is A $62$
Let the units digit $= x$
Let the tens digit $= x + 4$
Tens digit : One digit :: $3 : 1$
$x + 4 : x :: 3 : 1$
$\Rightarrow x + 4 = 3 x$
$\Rightarrow 2 x = 4$
$\Rightarrow x = 2$
Tens digit $= 6$
Therefore, the number is $62$ .

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The ten's digit of a two digit number exceeds its unit's digit by 4. If the ten's digit and the unit's digit are in the ratio 3:1, find the number.

The correct option is A 62Let the units digit =xLet the tens digit =x+4Tens digit : One digit :: 3:1x+4:x::3:1⇒x+4=3x⇒2x=4⇒x=2Tens digit =6Therefore, the number is 62.

The ten's digit of a two digit number exceeds its unit's digit by $4$ . If the ten's digit and the unit's digit are in the ratio $3 : 1$ , find the number.

The correct option is A $62$
Let the units digit $= x$
Let the tens digit $= x + 4$
Tens digit : One digit :: $3 : 1$
$x + 4 : x :: 3 : 1$
$\Rightarrow x + 4 = 3 x$
$\Rightarrow 2 x = 4$
$\Rightarrow x = 2$
Tens digit $= 6$
Therefore, the number is $62$ .