Sum of the digits of a two-digit number is 8. The digit in tens place is thrice the digit in unit place. Find the number.

Open in App

Solution

$Let the digit in unit place be x . So, the digit in tens place will be 3 x .$

According to the given data,

$3 x + x = 8 4 x = 8 x = \frac{8}{4} x = 2$

$Digit in unit place is 2. The digit in tens place is 3 \times 2 = 6$

$So, the number is 62.$

Suggest Corrections

Similar questions

In a two-digit number, the digit at the units place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

Q. Sum of digits of a two digit number is 8. The digit in tens place is thrice the digit in unit place. Find the number.

Q. Sum of two digits of two digits is 8. The digit in tens place is thrice the digit in unit place. Find the number.

sum of the digit of two digits number is 8 the digit in tens place is thrice the digit in unit place find the number

Sum of digit of two number is 8. The digit in tens place is thrice the digit in unit place in unit place. Find the numbers?

Join BYJU'S Learning Program

Sum of the digits of a two-digit number is 8. The digit in tens place is thrice the digit in unit place. Find the number.

Let the digit in unit place be x.So, the digit in tens place will be 3x. According to the given data, 3x+x=84x=8x=84x=2 Digit in unit place is 2. The digit in tens place is 3×2=6 So, the number is 62.

$Let the digit in unit place be x . So, the digit in tens place will be 3 x .$

According to the given data,

$3 x + x = 8 4 x = 8 x = \frac{8}{4} x = 2$

$Digit in unit place is 2. The digit in tens place is 3 \times 2 = 6$

$So, the number is 62.$