The correct option is B 55
Let S10 denote the sum to first 10 natural numbers.
S10=1+2+3+4+5+6+7+8+9+10 ----(1)
Reversing the numbers and adding will not change the sum and hence,
S10=10+9+8+7+6+5+4+3+2+1 ----(2)
Adding equation (1) & (2)
2S10=11+11+11+11+11+11+11+11+11+11
2S10=11×10
⇒ S10=(11×10)2=55