Question

Sum of the interior angles of a regular pentagon =

• A. ${180}^{\circ }$
• B. ${360}^{\circ }$
• C. ${540}^{\circ }$
• D. ${640}^{\circ }$

Answer 1

The correct option is C ${540}^{\circ }$

We have,

the sum of interior angles of a regular polygon of n sides = $(n-2)\times {180}^{\circ }$

$\therefore$ The sum of interior angles of a regular pentagon = $(5-2)\times {180}^{\circ }$ = $3\times {180}^{\circ }$ = ${540}^{\circ }$