Question

Sum of two numbers is 4 more than twice of difference of the two numbers. If one of the two numbers is three more than the other number, find the numbers.

• A. (, )
• B. (1,3)
• C. ( ,3)
• D. (1,2)

Answer 1

The correct option is A

(, )

Let one number be x and other be y

1st case: x + y = 4 + 2(x - y)
$\Rightarrow$ x + y = 4 + 2x - 2y
$\Rightarrow$ x - 3y + 4 = 0 ------------(i)

2nd case: x = 3 + y -----------(ii)

Substitute (ii) in (i), (3 + y) - 3y + 4 = 0
$\Rightarrow$ y = $\frac{7}{2}$

Put value of y in (ii), x = 3 + $\frac{7}{2}$ = $\frac{13}{2}$