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Question

Sum of  two numbers is 4 more than  twice of difference of the two numbers. If one of the two numbers is three more than the other number, find the numbers.



A

()

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B

(1,3)

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C

( ,3)

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D

(1,2)

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Solution

The correct option is B

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Let one number be x and other be y

1st case: x + y = 4 + 2(x - y)   
x + y = 4 + 2x - 2y 
 x - 3y + 4 = 0 ------------(i)

2nd case: x = 3 + y -----------(ii)

Substitute (ii) in (i), (3 + y) - 3y + 4 = 0 
y =  72

Put value of y in (ii), x = 3 +  72132


Mathematics

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