Sum to the 'n' terms of the series whose n^{th } term is 2^{n-1} + 8n^3 - 6n^2

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Sum of $n$ terms of the series whose $n^{t h}$ term is $2^{n - 1} + 8 n^{3} - 6 n^{2}$ .

n

n^{t h}

4 n (n^{2} + 1) - (6 n^{2} + 1)

Find the sum to n terms of the series whose n^th terms is given by (2n – 1)²

n

n t h

n^{2} + 2^{n}

n

n^{t h}

\frac{n^{3} + 3 n^{2} + 2 n + 2}{n^{2} + 2 n}

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