129

You visited us 129 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Boyle's Law

Sumit evacuat...

Question

Sumit evacuated a cylinder and filled in $4 g$ of gas $A$ at temperature $25^{o} C$ . The pressure was found to be $1 a t m$ . His friend Vineet, filled another $8 g$ of gas $B$ in the cylinder at the same temperature. The final pressure was found to be $1.5 a t m$ . The ratio of molecular masses of $A$ and $B$ (assuming ideal gas behaviour) is ____.

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1 : 4$
Option $D .$
Using $P V = n R T$ for gas $A .$
$1 \times V = n_{A} R T$
$V = (\frac{4}{M_{A}}) R T ⟶ i .$
After addition of gas $B,$
$1.5 V = (\frac{4}{M_{A}} + \frac{8}{M_{B}}) R T ⟶ i i$
$\frac{(2)}{(1)} ⟹ 1.5 = (\frac{4}{M_{A}} + \frac{8}{M_{B}}) \frac{M_{A}}{4} = 1 + 2 \frac{M_{A}}{M_{B}}$
$0.5 = 2 \frac{M_{A}}{M_{B}}$
$\frac{M_{A}}{M_{B}} = \frac{0.5}{2} = \frac{1}{2 \times 2} = \frac{1}{4}$

Suggest Corrections

Similar questions

Q. When

2 g

of a gaseous substance

A

is introduced into an initially evacuated flask at

25^{\circ} C

, the pressure is found to be

1

atmosphere.

3 g

of another gaseous substance

B

is then added to it at the same temperature and pressure. The final pressure is found to be

1.5

atmosphere. Calculate the ratio of molecular masses of

A

and

B

assuming ideal gas behaviour.

Q. When

2

g of gas A is introduced into an evacuated flask kept at

25^{o} C

, the pressure was found to be

1

atmosphere. If

3

g of another gas B is then added to the same flask, the pressure becomes

1.5

atm. Assuming ideal behaviour, the ratio of molecular weights

(M_{B} : M_{A})

is :

Q. When

2

g of gas A is introduced into an evacuated flask kept at

25^{o} C

, the pressure was found to be

1

atm. If

3

g of another gas B is then added to the same flask containing A, the pressure becomes

1.5

atm. Assuming ideal behaviour, the ratio of molecular weights

(M_{A} : M_{B})

is :

When 2 g of a gas is introduced into an evacuated flask kept at $25^{\circ} C$ , the pressure is found to be 1 atmosphere. If 3 g of another gas B is then added to the same flask, the total pressure becomes 0.5 atmosphere. Assuming ideal gas behaviour, calculate the ratio of molecular mass $M_{A} : M_{B}$ .

Q. When

2 g

of a gas A is introduced into an evacuated flask kept at

25^{\circ} C

, the pressure is found to be

1 a t m

. If

3 g

of another gas B is then added to the same flask at the same temperature, the total pressure becomes

1.5 a t m

. Assuming ideal gas behaviour, the value of

\frac{M_{B}}{M_{A}}

to the nearest integer is :

Join BYJU'S Learning Program

The correct option is D 1:4Option D.Using PV=nRT for gas A.1×V=nARTV=(4MA)RT⟶i.After addition of gas B,1.5V=(4MA+8MB)RT⟶ii(2)(1)⟹1.5=(4MA+8MB)MA4=1+2MAMB0.5=2MAMBMAMB=0.52=12×2=14