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Pressure

Sumit has a c...

Question

Sumit has a cube of side 0.2m of mass 50 kg. The pressure exerted by the cube on the table is

(Take g = $10 m / s^{2}$ )

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Solution

$P r e s s u r e = \frac{F o r c e}{A r e a} P = \frac{50 \times 10}{0.04} = 12500 N m^{- 2}$

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