Question

Sunita is twice as old as Ashima. If six years is substracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times Ashima's age. How old were they two years ago ?

Answer 1

Let age of Ashima = x

Then age of Sunita = 2x

According to the condition :

4(x-6)=2x+4

$\Rightarrow 4x-24=2x+4\Rightarrow 4x-2x=4+24$

$\Rightarrow 2x=28\Rightarrow x=\frac{28}{2}=14$

$\therefore$ Sunita's present age $2x=2\times 14=28$ years and Ashima's age = 14 years

Two years ago,

Age of Sunita = 28-2=26 years and age of Ashima = 14 - 2 = 12 years