Question

Sunita is twice as old as Ashima. If six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times Ashima's age. How old were they two years ago?

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{age}\mathrm{of}\mathrm{Ashima}\text{be}\mathrm{x}\mathrm{years}. \\ \mathrm{Therefore},\mathrm{the}\mathrm{age}\mathrm{of}\mathrm{Sunita}\mathrm{will}\mathrm{be}2\mathrm{x}\mathrm{years}. \\ \mathrm{According}\mathrm{to}\mathrm{the}\mathrm{question}, \\ 4(\mathrm{x}-6)=2\mathrm{x}+4 \\ \mathrm{or}4\mathrm{x}-24=2\mathrm{x}+4 \\ \mathrm{or}4\mathrm{x}-2\mathrm{x}=4+24 \\ \mathrm{or}2\mathrm{x}=28 \\ \mathrm{or}\mathrm{x}=14 \\ \therefore \mathrm{Age}\mathrm{of}\mathrm{Ashima}=14\mathrm{years}. \\ \mathrm{Age}\mathrm{of}\mathrm{Sunita}=2\times 14=28\mathrm{years}. \end{gathered}$$