CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
235
You visited us 235 times! Enjoying our articles? Unlock Full Access!
Question

Suppose a block of mass 1 kg is placed over a rough surface and a horizontal force F is applied on the block as shown in figure. Now, let us see what are the values of force of friction f and acceleration of the block a if the force F is gradually increased. Given that μs=0.5,μk=0.4 and (g= 10m/s2).
245557_394771152ba545658349a6d7dbb87f6f.png

Open in App
Solution

From the graph it is clear that the maximum frictional force we can get is maximum static friction
fs=μsN
fs=0.5×1×10
fs=5N

After this if we increase the force the block will start moving and there is a constant frictional force will act on the block that force is call kinetic frictional force and the value of kinetic frictional force is
fk=μkN
fs=0.4×1×10
fs=4N

now the acceleration the block will be
a=FμkNM
a=F41
acceleration (a)=F4

596725_245557_ans_982f3bdf01ea44529a9ccab54c2f1203.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon