Question

Suppose that a box is accelerating at a rate of 2 m/$s^2$ If the net force is tripled and the mass is doubled, then what is the new acceleration of the box?

• A. 2 m/$s^2$
• B. 3 m/$s^2$
• C. 4 m/$s^2$
• D. 0 m/$s^2$

Answer 1

The correct option is (B) 3 m/$s^2$

According to the question

Let F be the force acting on the body with mass M.

given acceleration a = 2 m/$s^2$

From the Newton's second law we know

$F=Ma$

Or, $2=\frac{F}{M}$

Now, the force is triple and mass is doubled.

So we can write

$F_1=3F,M_1=2M$

$a_1$ be the new acceleration

$F_1=M_1{a}_1$

$⟹a_1=\frac{F_1}{M_1}=\frac{3F}{2M}$

From (1) the value of $\frac{F}{M}=2$

So, $a_1=\frac{3}{2}\times 2=3$ m/$s^2$

Hence the new acceleration is 3 m/$s^2$