Suppose the tangent to the parabola y=x2+px+q at (0,3) has slope −1. Then p+q equals.
If the equation of the tangent to the circle x=3+5cos θ, y=−1+5sinθ at the point (0,3) is px+qy+r =0 and p>0 then p + q =
If the equation of the tangent to the circle x=3+5cos θ, y=−1+5sinθ at the point (0,3) is Px+qy+r =0 and p>0 then p + q =