The tangent to the ellipse x 2 - 4 - y 2 - 3 -1 with slope 3 y-px -39 then p-

Let the slope of tangent be m The equation of tangent with slope m to ellipse x^24+y^23=1 is y=mx±√(4 m^2+3) given m=3 put m=3 we gety=3x+ ...

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Standard XII

Mathematics

Point Form of Tangent: Ellipse

The tangent t...

Question

The tangent to the ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1$ with slope 3 y=px $\pm \sqrt{(} 39)$ then p=

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Solution

Let the slope of tangent be $m$
The equation of tangent with slope $m$ to ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1$ is $y = m x \pm \sqrt{4 m^{2} + 3}$

given m=3 put m=3 we get
y=3x+ $\sqrt{(} 39)$

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The tangent to the ellipse x24+y23=1 with slope 3 y=px ±√(39) then p=

Let the slope of tangent be mThe equation of tangent with slope m to ellipse x24+y23=1 is y=mx±√4m2+3given m=3 put m=3 we gety=3x+√(39)

The tangent to the ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1$ with slope 3 y=px $\pm \sqrt{(} 39)$ then p=

Let the slope of tangent be $m$
The equation of tangent with slope $m$ to ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1$ is $y = m x \pm \sqrt{4 m^{2} + 3}$

given m=3 put m=3 we get
y=3x+ $\sqrt{(} 39)$