Suppose the tangent to the parabola $y = x^{2} + p x + q$ at $(0, 3)$ has slope $- 1$ . Then $p + q$ equals

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Solution

The correct option is C $2$
Putting point $(0, 3)$ in the parabola,
$y = q = 3$
Now the slope of the tangent,
$\frac{d y}{d x} = 2 x + p \Rightarrow - 1 = p$
Hence $p + q = - 1 + 3 = 2$

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Suppose the tangent to the parabola y=x2+px+q at (0,3) has slope –1. Then p+q equals

The correct option is C 2Putting point (0,3) in the parabola, y=q=3 Now the slope of the tangent, dydx=2x+p⇒−1=p Hence p+q=−1+3=2

Suppose the tangent to the parabola $y = x^{2} + p x + q$ at $(0, 3)$ has slope $- 1$ . Then $p + q$ equals

The correct option is C $2$
Putting point $(0, 3)$ in the parabola,
$y = q = 3$
Now the slope of the tangent,
$\frac{d y}{d x} = 2 x + p \Rightarrow - 1 = p$
Hence $p + q = - 1 + 3 = 2$