Question

Suppose $△ABC$ has to be constructed in such a way that $BC=5$ cm, $\angle ABC={30}^{\circ }$ & $AB-AC=0$. The triangle is a/an triangle.

• A. equilateral
• B. scalene
• C. isosceles
• D. right-angled

Answer 1

The correct option is C isosceles

$\text{Given:}AB-AC=0$
That means side AB is equal to side AC.
So, the triangle is an isosceles triangle.