Surekha travels $10 k m$ to reach her office she walks $0.5 k m$ on foot at a speed of $8 k m p h$ to catch a bus which travels at a speed of $40 k m p h$ What is the time taken by Surekha to reach the office?

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Solution

Total distance traveled to reach the office $(D) = 10 k m$
Let us consider the motion during the walk.
$V =$ Speed of Surekha during the walk $= 8 k m / h$
$d =$ Distance traveled during walk $= 0.5 k m$
Given that
Let time spent during the walk $= t$
Time spent during the walk, $t = \frac{d}{v}$
$= \frac{0.5}{8} = 0.0625 h o u r$
By Bus
Now consider the motion during travel by bus:
$V =$ Speed of bus $= 40 k m / h$
$d' =$ distance remaining to travel to reach office $= D - d = 10 - 0.5 = 9.5 k m$
$t' =$ time spent traveling by bus
Time spent traveling by bus $t' = \frac{d'}{v}$
$t' = \frac{9.5}{40} = \frac{95}{10 \times 40}$
$t' = \frac{19}{80} = 0.2375 h o u r$
Total time taken to reach the office is given as,
$T = t + t'$
$T = 0.0625 + 0.2375$
$T = 0.3 h$
$T = 0.3 x 60 m i n u t e s = \frac{3}{10} x 60 m i n u t e s = 3 \times 6 m i n u t e s = 18 m i n u t e s$
Hence, the time is taken by Surekha to reach the office $= 18 m i n u t e s$ .

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Surekha travels 10km to reach her office she walks 0.5km on foot at a speed of 8kmph to catch a bus which travels at a speed of 40kmph What is the time taken by Surekha to reach the office?

Surekha travels $10 k m$ to reach her office she walks $0.5 k m$ on foot at a speed of $8 k m p h$ to catch a bus which travels at a speed of $40 k m p h$ What is the time taken by Surekha to reach the office?