Question

Sweets were distributed among 5 children namely A, B , C , D and E.

A got 13 Sweets and after that each child got 2 more than the previous child.

What is the average number of sweets each child got?

• A. 18
• B. 17
• C. 15
• D. 14

Answer 1

The correct option is B

17

A got 13 sweets

B got 13 + 2 = 15

C got 15 + 2 = 17

D got 17 + 2 = 19

E got 19 + 2 = 21

$\therefore$ Average number of sweets each got = $\frac{13+15+17+19+21}{5}$ = $\frac{85}{5}$ = 17

Alternate method :

Since, the Number of sweets increases by same number, the Mid value i.e. The value of C in this case will be the mean

(Because the number of observations is odd)