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Zero Order Reaction

t1/2 v/s 1a2 ...

Question

$t_{1 / 2} v / s \frac{1}{a^{2}}$ is straight line graph then determine the order of a reaction:

zero order

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first order

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second order

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third order

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Solution

The correct option is D third order
In general for an $n^{t h}$ order of a reaction, the half life period is given by,
$t_{1 / 2} \propto \frac{1}{a^{n - 1}}$ , $a$ = initial concentration; $n$ = order of reaction
Given, $t_{1 / 2}$ $v / s$ $1 / a^{2}$ i.e, $n - 1 = 2, n = 3$
$∴ t_{1 / 2}$ = (constant) $\frac{1}{a^{2}}$ is a straight line.
for $n = 3$ i.e, for Third order reaction.

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t1/2v/s1a2 is straight line graph then determine the order of a reaction:

The correct option is D third orderIn general for an nth order of a reaction, the half life period is given by,t1/2∝1an−1, a= initial concentration; n= order of reactionGiven, t1/2 v/s 1/a2 i.e, n−1=2,n=3∴t1/2= (constant)1a2 is a straight line.for n=3 i.e, for Third order reaction.

$t_{1 / 2} v / s \frac{1}{a^{2}}$ is straight line graph then determine the order of a reaction: