Question

T.V. tower has a height 100m. What is the population density around the T.V. tower if the total population covered is 50 lac? Radius of earth = $6.4\times {10}^{6}m$.

• A. 3242.9${k/m}^2$
• B. 1242.9${k/m}^2$
• C. 2242.9${k/m}^2$
• D. 4242.9${k/m}^2$

Answer 1

Answer: (B)

1242.9${k/m}^2$

Population covered is given by P= $p\times \pi d^2=\rho \times \pi 2hR$

where $h=100m$ and $\rho$ is population density

Population covered =50 lac, $R=6.4\times {10}^6$

Putting values

$50\times {10}^5=\rho \times \pi \times 2\times 100\times 6.4\times {10}^6$

$\rho =1242.9k/m^2$