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Question

Take 1L of a mixture of CO and CO2. Pass this mixture through a tube containing red hot charcoal. The volume now becomes 1.6L. The volumes are measured under the same conditions. Find the composition of the mixture by volume.

A
0.3 L
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B
0.6 L
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C
0.9 L
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D
None of the above
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Solution

The correct option is A 0.6 L
Let the volume of CO in the mixture be V.
The volume of CO2 in the mixture is (1V).
CO2+C2CO
(1V)L CO2 forms 2(1V)L CO.
Total CO:
V+2(1V)=1.6
or, V=0.4
CO=0.4L
CO2=1V=0.6L=600ml

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