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Condition for Two Lines to Be Parallel

Take 1 cm =...

Question

Take $1 c m = 1$ units on $x$ -axis and $1 c m = 1$ unit on $y$ -axis. Solve graphically the following equations:
$3 x + 5 y = 12$ ; $3 x - 5 y + 18 = 0$

x = 1, y = 4

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x = - 1, y = 2

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x = - 1, y = 3

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x = 1, y = 9

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Solution

The correct option is C $x = - 1, y = 3$
Plotting $3 x + 5 y = 12$ and $3 x - 5 y + 18 = 0$ in the graph,we get
the point of intersection is $(- 1, 3)$

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Similar questions

2 c m = 2

x

1 c m = 1

y

3 x + 5 y = 12; 3 x - 5 y + 18 = 0

\frac{x + y}{2} + \frac{3 x - 5 y}{4} = 2, \frac{x}{14} + \frac{y}{18} = 1

1 c m = 1

x - 2 y - 4 = 0

2 x + y = 3

2 y - x = 8

5 y - x = 14

y - 2 x = 1

1 c m = 1

1) Solve graphically the following equations :

x+2y=4 , 3x -2y =4 . take 2cm = 1 unit on eachaxis. Write down the area of the triangle formed by the lines and the x- axis.

2) on graph paper take 2 cm to represent one unit on both the axes draw the lines:

x+3= 0, y-2=0, 2x+3y=12. Write down the coordinates of the vertices of the triangle formed by the lines

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