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Question

Solve: x+y2+3x−5y4=2,x14+y18=1

A
7,8
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B
7,9
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C
6,10
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D
None
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Solution

The correct option is B 7,9
Given,
x+y2+3x5y4=2.............Eq(1)
x14+y18=1....................Eq(2)
On solving eq (1) we get
x+y2+3x5y4=2
2(x+y)+(3x5y)4=2
2x+2y+3x5y=8
5x3y=8.............................Eq(3)..multiplied by 7
on solving Eq(2) we get
x14+y18=1
9x+7y126=1
9x+7y=126..........................Eq(4)...multipied by3
on adding both Eq 3 and Eq 4 we get
35x21y=56
27x+21y=378
_________________________
62x=434
x=43462=7
putting the value of x=7 in eq 4 we get
9×7+7y=126
7y=12663
7y=63
y=637=9
Hence x=7 and y=9

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