Taking the set of natural numbers as the universal set, write down the complement of the following sets :
(i) {x : x is an even natural number}
(ii) {x : x is an odd natural number}
(iii) {x : x is a positive multiple of 3}
(iv) {x : x is a prime number}
(v) {x : x is a natural number divisible by 3 and 5}
(vi) {x : x is a perfect square}
(vii) {x : x is a perfect cube}
(viii) {x : x + 5 = 8}
(ix) {x : 2x + 5 = 9}
(x) {x : x ≥ 7}
(xi) {x : x ∈ N and 2x + 1 > 10}
Here U = {x : x ∈ N}
(i) Let A = {x : x is an even natural number}
A′ = U - A
= {x : x ∈ N} - {x : x is an even natural number}
= {x : x is an odd natural number}
(ii) Let A = {x : x is an odd natural number}
A′ = U - A
= {x : x ∈ N} - {x : x is an odd natural number}
= {x : x is an even natural number}
(iii) Let A = {x : x is a positive multiple of 3}
∴ A′ = U - A
= {x : x ∈ N} - {x : x is a positive multiple of 3}
= {x : x ∈ N, x is not a multiple of 3}
(iv) Let A = {x : x is a prime number}
A′ = U - A
= {x : x ∈ N} - {x : x is a prime number}
= {x : x ∈ N, x is not a prime number} or {x : x is positive composite number and x = 1}
(v) Let A = {x : x is a natural number divisible by 3 and 5}
A′ = U - A
= {x : x ∈ N} - {x : x is a natural number divisible by 3 and 5}
= {x : x ∈ N} - {x : x is a natural number divisible by 15}
= {x : x ∈ N, x is not divisible by 15}
(vi) Let A = {x : x is a perfect square}
A′ = U - A
= {x : x ∈ N} - {x : x is a perfect square}
= {x : x ∈ N, x is not a perfect square}
(vii) Let A = {x : x is a perfect cube}
A′ = U - A
= {x : x ∈ N} - {x : x is a perfect cube}
= {x : x ∈ N, x is not a perfect cube}
(viii) Let A = {x : x + 5 = 8} = {3}
A′ = U - A
= {x : x ∈ N} - {3} = {x : x ∈ N, x ≠ 3}
(ix) Let A = {x : 2 x + 5 = 9} = {2}
A′ = U - A = {x : x ∈ N} - {2}
= {x : x ∈ N, x ≠ 2}
(x) Let A = {x : x ≥ 7} = {7, 8, 9, 10, ..........}
A′ = U - A
= {x : x ∈ N} - {7, 8, 9, 10, ..........}
= {1, 2, 3, 4, 5, 6}
= {x : x ∈ N and x < 7}
(xi) Let A = {x : x ∈ N and 2x + 1 > 10}
= {5, 6, 7, 8, .........}
A′ = U - A
= {x : x ∈ N} - {5, 6, 7, 8,..........}
= {1, 2, 3, 4}