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Byju's Answer
Standard XII
Physics
Introduction
tan 20 0 +tan...
Question
t
a
n
20
0
+
t
a
n
40
0
+
.
.
.
.
.
.
.
.
.
.
+
t
a
n
180
0
=
Open in App
Solution
=
tan
20
+
tan
40
+
tan
60
+
tan
80
+
.
.
.
.
.
tan
180
=
tan
20
+
tan
40
+
tan
60
+
tan
80
+
tan
(
180
−
100
)
+
tan
(
100
−
120
)
+
tan
(
100
−
140
)
+
tan
(
100
−
160
)
+
tan
(
100
−
180
)
=
tan
20
+
tan
40
+
tan
60
+
tan
80
−
tan
20
−
tan
40
−
tan
60
−
tan
80
=
0
.
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0
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