$tan 43^{o}$ $tan 45^{o}$ $tan 47^{o}$ is equal to

\sqrt{3}

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\frac{1}{\sqrt{3}}

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1

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2

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Solution

The correct option is B $1$
$\tan 43^o\cdot\tan 45^o
\cdot \tan 47^o$
$= tan 43^{o} \cdot tan (90^{o} - 43^{o}) \cdot tan 45^{o}$
$= tan 43^{o} \times cot 43^{o} \times 1$
$= 1 \times 1 = 1$

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Similar questions

(1 + tan 1^{o}) (1 + tan 2^{o}) (1 + tan 3^{o}) . . . . . . . . . . . . (1 + tan 45^{o})

(1 + tan 1^{o}) (1 + tan 2^{o}) (1 + tan 3^{o}) . . . . (1 + tan 45^{o}) = 2^{n}

n

\frac{1 - c o s 2 θ}{1 + c o s 2 θ} = 3

θ

tan 45^{o} \times tan 8^{o} \times tan 82^{o}

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2 \sqrt{3} tan θ = 6

\frac{1 - {tan}^{2} θ}{1 + {tan}^{2} θ} = \frac{1}{2}

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