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Question

tanx+tan2x+tan3x=tanx.tan2x.tan3x
find its general solutionn

A
x=n
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B
x=n+3
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C
x=2n
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D
x = n3
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Solution

The correct option is D x = n3
Tanx+Tan2x+Tan3x=Tanx Tan2xTan3x _ (1) (Given)
Tan(3x)=Tan(x+2x)=Tanx+Tan2x1TanxTan2x
Tan3xTanx Tan2x Tan3x=Tanx+Tan2x
Tanx+Tan2xTan3x=Tanx Tan2x Tan3x_ (2)
(1) + (2) Tan3x=0Tan3x=0
3x=K
x=k3

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