tan3 A = sin 45 $°$ cos 45 $°$ + sin 30 $°$

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Solution

tan 3A = sin 45^o cos 45^o + sin 30^o

$\Rightarrow \tan 3 A = \frac{1}{\sqrt{2}} \times \frac{1}{\sqrt{2}} + \frac{1}{2} (From the table) \Rightarrow \tan 3 A = \frac{1}{2} + \frac{1}{2} \Rightarrow \tan 3 A = 1 \Rightarrow \tan 3 A = \tan 45 ° (From the table) \Rightarrow 3 A = 45 ° \Rightarrow A = 15 °$

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Similar questions

tan 3 A =

sin 45^{\circ} cos 45^{\circ} + sin 30^{\circ}

(cos 0^{\circ} + sin 45^{\circ} + sin 30^{\circ}) (sin 90^{\circ} - cos 45^{\circ} + cos 60^{\circ}) =

(c o s 0^{\circ} + s i n 45^{\circ} + s i n 30^{\circ}) (s i n 90^{\circ} - c o s 45^{\circ} + c o s 60^{\circ})

What is the value of $\frac{sin 45^{\circ} sin 30^{\circ}}{cos 45^{\circ} cos 30^{\circ}}$ ?

(cos 0^{\circ} + sin 45^{\circ} + sin 30^{\circ}) (sin 90^{\circ} - cos 45^{\circ} + cos 60^{\circ})

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