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Position of a Line W.R.T Hyperbola

Tangent to th...

Question

Tangent to the ellipse x^2 + 4 y^2=1 makes angle 60 degrees with the focal distance of the point of contact ,then the square of the slope of the tangent is (A)1 (B)2 (C)3 (D)none of these

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\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

α

β

\frac{cos β}{cos α}

\frac{x^{2}}{28} + \frac{y^{2}}{16} = 1

60^{\circ}

x -

x^{2} - y^{2} = 5

\frac{x^{2}}{9} + \frac{y^{2}}{4} = 1

α

β

\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1

\pm \sqrt{(} 39)

(x_{1}, y_{1})

(x_{2}, y_{2})

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x_{1} x_{2}}{y_{1} y_{2}}

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