Tautomerism is not observed in :

{C H}_{3} - C | | O - {C H}_{3}

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P h - C H = C H - O H

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{C H}_{3} - {N O}_{2}

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{C H}_{3} -_{3} - C H O

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Solution

The correct option is D ${C H}_{3} -_{3} - C H O$
Solution:- (D) ${(C H_{3})}_{3} - C - C H O$
For an aldehyde $(- C H O)$ or a ketone $(R_{2} C = O)$ to exhibit tautomerism, it is essential that it must have at least one $α - H$ atom.
Hence, $C H O - C - {(C H_{3})}_{3}$ will not show tautomerism as it does not have $α$ hydrogen atom.

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Similar questions

C H_{3} - O | | C - C H | C H_{3} - C H | C H O - C H | C H_{3} - C H_{3}

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

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