Taylor purchased a rectangular plot of area 634m2. The length of the plot is 2 more than thrice its breadth. Find the length and breadth (approximate values).
44.6m & 14.20m
Let x and y be the length and breadth of the rectangle respectively.
Given, x= 2+3y
Area of the rectangle = length × breadth = xy
⇒ 634= (2+3y)y
⇒ 634= 2y+3y2
So, 3y2 +2y- 634 = 0
By solving the quadratic equation, we get, x = 44.6m and y = 14.20m (approximately).