Taylor purchased a rectangular plot of area $634 m^{2}$ . The length of the plot is $2 m$ more than thrice its breadth. Find the length and breadth (approximate values).

34.6m & 11.20m

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88m & 24m

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32m &16m

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44.6m & 14.20m

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Solution

The correct option is D
44.6m & 14.20m

Let $x$ and $y$ be the length and breadth of the rectangle respectively.
Given, $x = 2 + 3 y$
Area of the rectangle =
length $\times$ breadth = $x y$
$\Rightarrow 634 = (2 + 3 y) y$
$\Rightarrow 634 = 2 y + 3 y^{2}$
So, $3 y^{2} + 2 y - 634 = 0$
By solving the quadratic equation, we get, $x = 44.6 a n d y = 14.20$ (approximately).

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Q. Taylor purchased a rectangular plot of area

634 m^{2}

. The length of the plot is 2 m more than thrice its breadth. Then find the approximate values of length and breadth of the plot.

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Taylor purchased a rectangular plot of area 634m2. The length of the plot is 2m more than thrice its breadth. Find the length and breadth (approximate values).

The correct option is D 44.6m & 14.20m Let x and y be the length and breadth of the rectangle respectively. Given, x=2+3y Area of the rectangle = length × breadth = xy ⇒634=(2+3y)y ⇒634=2y+3y2 So, 3y2+2y−634=0 By solving the quadratic equation, we get, x=44.6 and y=14.20 (approximately).

Taylor purchased a rectangular plot of area $634 m^{2}$ . The length of the plot is $2 m$ more than thrice its breadth. Find the length and breadth (approximate values).