Question

Team $‘A^{\prime }$ consists of $7$ boys and n girls and Team $‘B^{\prime }$ has $4$ boys and $6$ girls. If a
total of $52$ single matches can be arranged between these two teams when a
boy plays against a boy and a girl plays against a girl, then $n$ is equal to:

• A. $5$
• B. $6$
• C. $2$
• D. $4$

Answer 1

The correct option is D $4$

$7\times 4+6\times n=52\Rightarrow 6n=24\Rightarrow n=4$