Ted was having dinner with his younger cousin. Ted’s cousin could have only one roti whereas Ted’s capacity was 4 rotis. Assume that the rotis are perfect circles with radius 4 cm. To what radius should the rotis be reduced so that Ted’s cousin eats as many rotis as Ted?

3 cm

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3.5 cm

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2 cm

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1 cm

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Solution

The correct option is C
2 cm

One roti’s area = $π (4)^{2} = 16 π c m^{2}$

Cousin’s capacity is 1 roti = area of 1 roti = 16 $π c m^{2}$

Area of one roti has to be divided in 4 small rotis i.e. $\frac{16 π}{4} = 4 π c m^{2}$

So the new radius, r is

$π r^{2} = 4 π$

r = 2 cm

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Similar questions

A young cousin of yours had come for dinner at your place. He could have only one roti whereas your capacity is four rotis. Assume that the rotis are perfectly circular with radius $4 c m$ . But your cousin wanted to eat as many rotis as you could eat. So, your mum reduced the radius of his rotis to $_____$ .

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Ted was having dinner with his younger cousin. Ted’s cousin could have only one roti whereas Ted’s capacity was 4 rotis. Assume that the rotis are perfect circles with radius 4 cm. To what radius should the rotis be reduced so that Ted’s cousin eats as many rotis as Ted?

The correct option is C 2 cm One roti’s area = π(4)2=16π cm2 Cousin’s capacity is 1 roti = area of 1 roti = 16π cm2 Area of one roti has to be divided in 4 small rotis i.e. 16π4=4π cm2 So the new radius, r is π r2=4π r = 2 cm

The correct option is C
2 cm

One roti’s area = $π (4)^{2} = 16 π c m^{2}$

Cousin’s capacity is 1 roti = area of 1 roti = 16 $π c m^{2}$

Area of one roti has to be divided in 4 small rotis i.e. $\frac{16 π}{4} = 4 π c m^{2}$

So the new radius, r is

$π r^{2} = 4 π$

r = 2 cm