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Question

Tertiary butyl methyl ether on treatment with HI forms :

A
isobutane and methyl iodide
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B
isobutanol and methanol
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C
tertiary butyl iodide and methanol
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D
tertiary butyl iodide and methyl iodide
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Solution

The correct option is C tertiary butyl iodide and methanol

Tertiary butyl methyl ether on treatment with HI forms Tertiary butyl iodide and Methanol.

Since the tertiary carbocation forms which is stable so SN1 mechanism followed. Iodine is attached to tertiary C atom and -OH group is attached to methyl group.

509908_474890_ans.png

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