Question

$\text{ABC}$ is an equilateral triangle of side $2\text{m}$. If electric field $E=10{\text{NC}}^{-1}$ then the potential difference $V_A-V_B$ is

• A. $-20\text{V}$
• B. $20\text{V}$
• C. $-10\text{V}$
• D. $10\text{V}$

Answer 1

The correct option is C $-10\text{V}$

Given,
Electric field, $E=10{\text{NC}}^{-1}$


As we know that electric potential decreases along the direction of electric field, so $V_B>V_A$.

From the relation between electric field and electric potential,
$V_B-V_A=Ed$
Substituting the values from figure we get,
$V_B-V_A=10\times 1$

$\therefore V_A-V_B=-10\text{V}$

Hence, option (b) is the correct answer.