Benzene CH 2- CH - CH 3- H - M KMnO 4 H - KMn N SOCl 2- Y anhyd- AlCl 3- Benzene - ZChoose the incorrect option according to given reaction-A- Product N gives CO 2 gas with N aHCO 3B- Z react with H 2 N - OH and formed product show geometrical isomerismC- M forms cumenehydroperoxide with O 2 - -D- Z forms oxime with NH 2 OH and this oxime on reaction with H 2 SO 4 gives Ph - C O - NH - P h

The correct option is B Z react with H_2N OH and formed product show geometrical isomerism nbsp; Benzoic acid on treatment with sodium bicarbonate produces C ...

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Byju's Answer

Standard XII

Chemistry

Formation of Enamines

Benzene CH 2=...

Question

$Benzene C H_{2} = C H - C H_{3} - --------- \to H^{+} M H^{+} - ---- \to K M n O_{4} N S O C l_{2} - --- \to Y a n h y d . A l C l_{3} - ------- \to Benzene Z$

Choose the incorrect option according to given reaction.

Z react with

H_{2} N - O H

and formed product show geometrical isomerism

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Product N gives

C O_{2}

gas with

N a H C O_{3}

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M forms cumenehydroperoxide with

O_{2} / Δ

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Z forms oxime with

N H_{2} O H

and this oxime on reaction with

H_{2} S O_{4}

gives

P h - O | | C - N H - P h

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Solution

The correct option is A Z react with $H_{2} N - O H$ and formed product show geometrical isomerism

Benzoic acid on treatment with sodium bicarbonate produces $C O_{2}$ .

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Similar questions

Q. Assertion :

P h_{2} {B r}^{⊖}

on reaction with

N a O H

gives benzene diazohydroxide. Reason:

⊖ O H

is a strong nucleophile, attacks the terminal N atom, and forms a covalent bond.

Q. The smallest ketone and its next homologue are reacted with

N H_{2} O H

to form oxime:

Q. The smallest ketone and its next homologue are reacted with

N H_{2} O H

to form oxime:

Q. A compound X decolourises

B r_{2}

water and reacts slowly with conc.

H_{2} S O_{4}

to give an addition product. X reacts with HBr to form Y.Y reacts with NaOH to form, Z, On oxidation Z gives hexan-3-one. X,Y and Z in the reactions are :

Which of the following will form only one oxime on reaction with $N H_{2} O H$ solution?

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BenzeneCH2=CH−CH3−−−−−−−−−−→H+MH+−−−−−→KMnO4NSOCl2−−−−→Yanhyd. AlCl3−−−−−−−−→BenzeneZ Choose the incorrect option according to given reaction.

The correct option is A Z react with H2N−OH and formed product show geometrical isomerism Benzoic acid on treatment with sodium bicarbonate produces CO2.

$Benzene C H_{2} = C H - C H_{3} - --------- \to H^{+} M H^{+} - ---- \to K M n O_{4} N S O C l_{2} - --- \to Y a n h y d . A l C l_{3} - ------- \to Benzene Z$

Choose the incorrect option according to given reaction.

The correct option is A Z react with $H_{2} N - O H$ and formed product show geometrical isomerism

Benzoic acid on treatment with sodium bicarbonate produces $C O_{2}$ .